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Electrostatics question

2006 · Q141
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Electrostatics question

2006 · Q141

NEETPhysicsElectrostaticsMCQ+4 / −1
An electric dipole of moment p→\overrightarrow pp​ is lying along a uniform electric field E→\overrightarrow EE. The work done in rotating the dipole by 90o is
  1. A
    pE
  2. B
    2pE\sqrt 2 pE2​pE
  3. C
    pE/2
  4. D
    2pE
View written solutionFree

Correct answer: A

Work done in deflecting a dipole through an angle θ\theta θ is given by

W=∫0θpEsin⁡θdθ=pE(1−cos⁡θ)W = \int\limits_0^\theta {pE\sin \theta d\theta } = pE\left( {1 - \cos \theta } \right)W=0∫θ​pEsinθdθ=pE(1−cosθ)

Since θ\theta θ = 90°

∴\therefore∴ W = pE(1 – cos90°) ⇒\Rightarrow⇒ W = pE

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