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Electrostatics question

2004 · Q159
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Electrostatics question

2004 · Q159

NEETPhysicsElectrostaticsMCQ+4 / −1
A bullet of mass 2 g is having a charge of 2 μ\muμC. Through what potential difference must it be accelerated, starting from rst, to acquire a speed of 10 m/s ?
  1. A
    5 kV
  2. B
    50 kV
  3. C
    5 V
  4. D
    50 V
View written solutionFree

Correct answer: B

Using 12mv2=qV{1 \over 2}m{v^2} = qV21​mv2=qV

V=12×2×10−3×10×102×10−6=50 kVV = {1 \over 2} \times {{2 \times {{10}^{ - 3}} \times 10 \times 10} \over {2 \times {{10}^{ - 6}}}} = 50\,kVV=21​×2×10−62×10−3×10×10​=50kV

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