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Electromagnetic Waves question

2024 · Q186
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Electromagnetic Waves question

2024 · Q186

NEETPhysicsElectromagnetic WavesMCQ+4 / −1

If the ratio of relative permeability and relative permittivity of a uniform medium is 1:41: 41:4. The ratio of the magnitudes of electric field intensity (E)(E)(E) to the magnetic field intensity (H)(H)(H) of an EM wave propagating in that medium is (Given that μ0ε0=120π\sqrt{\frac{\mu_0}{\varepsilon_0}}=120 \piε0​μ0​​​=120π):

  1. A
    30π:130 \pi: 130π:1
  2. B
    1:120π1: 120 \pi1:120π
  3. C
    60π:160 \pi: 160π:1
  4. D
    120π:1120 \pi: 1120π:1
View written solutionFree

Correct answer: C

$$\frac{\mu_r}{E_r}=\frac{1}{4}$$

$$\begin{aligned} \frac{E}{H}=\frac{E \mu}{B} & =v \mu \\ =\frac{1}{\sqrt{\mu \varepsilon}} \mu & =\sqrt{\frac{\mu}{\varepsilon}}=\sqrt{\frac{\mu_0 \mu_r}{\varepsilon_0 \varepsilon_r}} \\ & =\sqrt{\frac{\mu_0}{\varepsilon_0}} \sqrt{\frac{\mu_r}{\varepsilon_r}} \\ & =120 \pi\left(\frac{1}{2}\right) \\ & =\frac{60 \pi}{1} \end{aligned}$$

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