NEETPhysicsElectromagnetic WavesMCQ+4 / −1
The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability and permittivity is (Given that c - velocity) of light in free space
- A
- Bc
- C
- D
View written solutionFree
Correct answer: C
We know,
$${{{E_0}} \over {{B_0}}}$$ (in vacuum) = c
$\therefore$ $${{{B_0}} \over {{E_0}}} = {1 \over c}$$
or, $${{{B_0}} \over {{E_0}}} = \sqrt {{\mu _0}{\varepsilon _0}} $$
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