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Electromagnetic Waves question

2018 · Q128
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Electromagnetic Waves question

2018 · Q128

NEETPhysicsElectromagnetic WavesMCQ+4 / −1
An EM wave is propagating in a medium with a velocity v→=vi^\overrightarrow v = v\widehat iv=vi. The instantaneous oscillating electric field of this em wave is along +y axis. Then the direction of oscillating magnetic field of the em wave will be along
  1. A
    z direction
  2. B
    +z direction
  3. C
    –y direction
  4. D
    –x direction
View written solutionFree

Correct answer: B

As we know,

E→×B→=V→\overrightarrow E \times \overrightarrow B = \overrightarrow V E×B=V

⇒\Rightarrow⇒ Ej^×B→=vi^E\widehat j \times \overrightarrow B = v\widehat iEj​×B=vi

[ As given Electric field vector is along +y axis and v→=vi^\overrightarrow v = v\widehat iv=vi ]

i^=j^×k^\widehat i = \widehat j \times \widehat ki=j​×k so B→=Bk^\overrightarrow B = B\widehat kB=Bk.

∴\therefore∴ Direction of magnetic field vector is along +z direction.

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