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Electromagnetic Waves question

2012 · Q88
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Electromagnetic Waves question

2012 · Q88

NEETPhysicsElectromagnetic WavesMCQ+4 / −1
The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagatting in vacuum is equal to
  1. A
    the speed of light in vacuum
  2. B
    reciprocal of speed of light in vacuum
  3. C
    the ratio of magnetic permeability to the electric susceptibility of vacuum
  4. D
    unity
View written solutionFree

Correct answer: B

If the speed of light c then

E0 = B0c

⇒\Rightarrow⇒ B0E0=1c{{{B_0}} \over {{E_0}}} = {1 \over c}E0​B0​​=c1​

Hence ratio of amplitude of magnetic field to amplitude of electric field for electromagnetic wave in a vacuum is reciprocal of speed of light.

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