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Electromagnetic Waves question

2012 · Q139
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Electromagnetic Waves question

2012 · Q139

NEETPhysicsElectromagnetic WavesMCQ+4 / −1
The electric field associated with an em wave in vacuum is given by
E = i^\widehat ii 40 cos (kz −-− 6 ×\times× 108 t) where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is
  1. A
    2 m−-−1
  2. B
    0.5 m−-−1
  3. C
    6 m−-−1
  4. D
    3 m−-−1
View written solutionFree

Correct answer: A

Compare the given equation with

E = E0cos(kz - ωt\omega tωt)

we get, ω\omega ω = 6 ×\times× 108 s-1

Wave vector, k = ωc{\omega \over c}cω​ = 6×1083×108{{6 \times {{10}^8}} \over {3 \times {{10}^8}}}3×1086×108​ = 2 m-1

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