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Electromagnetic Induction question

2016 · Q126
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Electromagnetic Induction question

2016 · Q126

NEETPhysicsElectromagnetic InductionMCQ+4 / −1
A long solenoid has 1000 turns. When a current of 4 A flows through it, the magnetic flux linked with each turn of the solenoid is 4 × 10−3\times \,{10^{ - 3}}×10−3 Wb. The self-inductance of the solenoid is
  1. A
    2 H
  2. B
    1 H
  3. C
    4 H
  4. D
    3 H
View written solutionFree

Correct answer: B

Total flux linked with the solenoid, ϕ\phi ϕ = Nϕ\phi ϕ0

= 1000 ×\times× 4 ×\times× 10-3 Wb = 4 Wb

∴\therefore∴ Self-inductance of solenoid

L = ϕI=44{\phi \over I} = {4 \over 4}Iϕ​=44​ = 1 H

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