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Electromagnetic Induction question

2013 · Q131
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Electromagnetic Induction question

2013 · Q131

NEETPhysicsElectromagnetic InductionMCQ+4 / −1
A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is
  1. A
    0.5 Wb
  2. B
    12.5 Wb
  3. C
    zero
  4. D
    2 Wb
View written solutionFree

Correct answer: B

Here, I = 2.5 A, L = 5 H

Magnetic flux linked with the coil is

ϕ\phi ϕB = LI = (5 H)(2.5 A) = 12.5 Wb

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