NEETPhysicsDual Nature of Radiation and MatterMCQ+4 / −1
The threshold frequency of a photoelectric metal is v0. If light of frequency 4v0 is incident on this metal, then the maximum kinetic energy of emitted electrons will be :
- A4 hv0
- Bhv0
- C2 hv0
- D3 hv0
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Correct answer: D
According to Einstein's photoelectric equation
$${(K.E)_{\max }} = hv - h{v_0}$$
$${(K.E)_{\max }} = h(4{v_0}) - h{v_0}$$
$${(K.E)_{\max }} = 3h{v_0}$$
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