NEETPhysicsDual Nature of Radiation and MatterMCQ+4 / −1
An electron is accelerated from rest through a potential difference of V volt. If the de-Broglie wavelength of the electron is 1.227 10-2 nm, the potential difference is :
- A102 V
- B103 V
- C104 V
- D10 V
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Correct answer: C
The de-Broglie wavelength and the accelerated potential is related as follows :
\lambda = {{12.27} \over {\sqrt V }}$$$A^\circ $
<br><br>\sqrt V = {{12.27 \times {{10}^{ - 10}}} \over {1.227 \times {{10}^{ - 11}}}} = {10^2}$$
volts
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