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Dual Nature of Radiation and Matter question

2017 · Q140
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Dual Nature of Radiation and Matter question

2017 · Q140

NEETPhysicsDual Nature of Radiation and MatterMultiple correct+4 / −1
The photoelectric threshold wavelength of silver is 3250 ×\times× 10−-−10 m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536 ×\times× 10−-−10 m is
{Given h = 4.14 ×\times× 10−-−15 eV s and c = 3 ×\times× 108 m s−-−1 ]
  1. A
    ≈\approx≈ 0.6 ×\times× 106 m s−-−1
  2. B
    ≈\approx≈ 61 ×\times× 103 m s−-−1
  3. C
    ≈\approx≈ 0.3 ×\times× 106 m s−-−1
  4. D
    ≈\approx≈ 6 ×\times× 105 m s−-−1
View written solutionFree

Correct answer: A, D

Minimum energy, E0 = 123753250{{12375} \over {3250}}325012375​ eV

⇒\Rightarrow⇒ E0 = 3.81 eV

Ultraviolet wavelength, λ\lambda λ = 2536 Ao\mathop A\limits^o Ao​

∴\therefore∴ Imparted energy, E = 123752536{{12375} \over {2536}}253612375​ = 4.88 eV

Now, max kinetic energy, 12mv2{1 \over 2}m{v^2}21​mv2 = E - E0

⇒\Rightarrow⇒ v = 2×1.07×1.6×10−199.1×10−31\sqrt {{{2 \times 1.07 \times 1.6 \times {{10}^{ - 19}}} \over {9.1 \times {{10}^{ - 31}}}}} 9.1×10−312×1.07×1.6×10−19​​

⇒\Rightarrow⇒ v = 0.61 × 106 m/s = 6.0 × 105 m/s

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