NEETPhysicsDual Nature of Radiation and MatterMCQ+4 / −1
A photosensitive metallic surface has work function, h0. If photons of energy fall on this surface, the electrons come out with a maximum velocity of 4 106 m/s. When the photon energy is increased to 5 h0, then maximum velocity of photoelectrons will be
- A2 107 m/s
- B2 106 m/s
- C8 106 m/s
- D8 105 m/s
View written solutionFree
Correct answer: C
2h = h +
5h = h +
=
v = 8 106 m/s
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