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Dual Nature of Radiation and Matter question

2001 · Q127
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Dual Nature of Radiation and Matter question

2001 · Q127

NEETPhysicsDual Nature of Radiation and MatterMCQ+4 / −1
In Thomson mass spectrograph E→⊥B→\overrightarrow E \bot \overrightarrow BE⊥B then the velocity of electron beam will be
  1. A
    ∣E→∣∣B→∣{{\left| {\overrightarrow E } \right|} \over {\left| {\overrightarrow B } \right|}}​B​​E​​
  2. B
    E→×B→\overrightarrow E \times \overrightarrow BE×B
  3. C
    ∣B→∣∣E→∣{{\left| {\overrightarrow B } \right|} \over {\left| {\overrightarrow E } \right|}}​E​​B​​
  4. D
    E→2B→2{{{{\overrightarrow E }^2}} \over {{{\overrightarrow B }^2}}}B2E2​
View written solutionFree

Correct answer: A

As eE = evB

∴\therefore∴ v = ∣E→∣∣B→∣{{\left| {\overrightarrow E } \right|} \over {\left| {\overrightarrow B } \right|}}​B​​E​​

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