NEETPhysicsCurrent ElectricityMCQ+4 / −1
The given circuit shows a uniform straight wire of length fixed at both ends. In order to get zero reading in the galvanometer , the free end of is to be placed from at:

- A32 cm
- B8 cm
- C16 cm
- D24 cm
View written solutionFree
Correct answer: D

$$\begin{aligned} \& \frac{8}{x}=\frac{12}{40-x} \\ \& \frac{2}{x}=\frac{3}{40-x} \\ \& 80-2 x=3 x \\ \& 16=x \end{aligned}$$
from $B$
$$=40-16=24 \mathrm{~cm}$$
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