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Current Electricity question

2000 · Q129
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Current Electricity question

2000 · Q129

NEETPhysicsCurrent ElectricityMCQ+4 / −1
Two bulbs of (40 W, 200 V), and (100 W, 200 V). Then correct relation for their resistances
  1. A
    R40 < R100
  2. B
    R40 > R100
  3. C
    R40 = R100
  4. D
    no relation can be predicted.
View written solutionFree

Correct answer: B

P=V2RP = {{{V^2}} \over R}P=RV2​

⇒R∝1P \Rightarrow R \propto {1 \over P}⇒R∝P1​

∴R40>R100 \therefore {R_{40}} \gt {R_{100}}∴R40​>R100​

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