NEETPhysicsCenter of Mass and CollisionMCQ+4 / −1
The distance covered by a body of mass 5 g having linear momentum 0.3 kg m/s in 5 s is :
- A0.3 m
- B300 m
- C30 m
- D3 m
View written solutionFree
Correct answer: B
$P = mv$
$$0.3 = 5 \times {10^{ - 3}}\,v$$
$v = {{300} \over 2}$
$v = 60$ m/s
$S = v \times t$
$ = 60 \times 5$
$ = 300$ m
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