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Capacitor question

2022 · Q144
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Capacitor question

2022 · Q144

NEETPhysicsCapacitorMCQ+4 / −1

The distance between the two plates of a parallel plate capacitor is doubled and the area of each plate is halved. If C is its initial capacitance, its final capacitance is equal to

  1. A
    C4{C \over 4}4C​
  2. B
    2C
  3. C
    C2{C \over 2}2C​
  4. D
    4C
View written solutionFree

Correct answer: A

For a capacitor of area A and distance between the plates as d, the capacitance (C) is

$$C = {{A{ \in _0}} \over d}$$

On doubling the distance and reducing area to half

$${C_1} = {{{A \over 2}{ \in _0}} \over {2d}}$$

$$ \Rightarrow {C_1} = {{A{ \in _0}} \over {4d}}$$

$$ \Rightarrow {C_1} = {C \over 4}$$

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