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Capacitor question

2022 · Q170
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Capacitor question

2022 · Q170

NEETPhysicsCapacitorMCQ+4 / −1

A capacitor of capacitance C = 900 pF is charged fully by 100 V battery B as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance C = 900 pF as shown in figure (b). The electrostatic energy stored by the system (b) is

NEET 2022 Phase 1 Physics - Capacitor Question 12 English

  1. A
    4.5 ×\times× 10−-−6 J
  2. B
    3.25 ×\times× 10−-−6 J
  3. C
    2.25 ×\times× 10−-−6 J
  4. D
    1.5 ×\times× 10−-−6 J
View written solutionFree

Correct answer: C

q1 = CV

= 900 $\times$ 10$-$12 $\times$ 100

= 9 $\times$ 10$-$8 C

NEET 2022 Phase 1 Physics - Capacitor Question 12 English Explanation 1

$$V = {{{C_1}{V_1} + {C_2}{V_2}} \over {{C_1} + {C_2}}}$$

$$ = {{9 \times {{10}^{ - 8}} + 0} \over {1800 \times {{10}^{ - 12}}}} = {{100} \over 2} = 50$$ V

$$U = {1 \over 2}({C_1} + {C_2}){V^2}$$

$$ = {1 \over 2} \times 1800 \times {10^{ - 12}} \times 50 \times 50$$

$$ = 225 \times {10^{ - 8}}$$

$$U = 2.25 \times {10^{ - 6}}$$ J

NEET 2022 Phase 1 Physics - Capacitor Question 12 English Explanation 2
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