NEETPhysicsAtoms and NucleiMCQ+4 / −1
Match List I with List II:
| List I (Spectral Lines of Hydrogen for transitions from) |
List II (Wavelengths (nm)) |
||
|---|---|---|---|
| A. | $$ $$ |
I. | 410.2 |
| B. | $$ $$ |
II. | 434.1 |
| C. | $$ $$ |
III. | 656.3 |
| D. | $$ $$ |
IV. | 486.1 |
Choose the correct answer from the options given below:
- AA-II, B-I, C-IV, D-III
- BA-III, B-IV, C-II, D-I
- CA-IV, B-III, C-I, D-II
- DA-I, B-II, C-III, D-IV
View written solutionFree
Correct answer: B
$$\begin{aligned} & \text { Energy difference } \Delta E=\frac{h c}{\lambda} \\ & \therefore \lambda \propto \frac{1}{\Delta E} \\ & (\Delta E)_{6-2}>(\Delta E)_{5-2}>(\Delta E)_{4-2}>(\Delta E)_{3-2} \\ & \lambda_{6-2}<\lambda_{5-2}<\lambda_{4-2}<\lambda_{3-2} \end{aligned}$$
A-III, B-IV, C-II, D-I
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