$$ \begin{aligned} & \frac{1}{\lambda}=\mathrm{R}\left(\frac{1}{(1)^2}-\frac{1}{\mathrm{n}^2}\right) \mathrm{n}=2,3,4, \ldots \ldots \\ & \left(\frac{1}{\lambda_{\mathrm{L}}}\right)_{\max }=\mathrm{R}\left(\frac{1}{(1)^2}-\frac{1}{(2)^2}\right) \quad\left(\because \frac{1}{\mathrm{R}} \simeq 912 \mathop A\limits^o\right) \\ & \left(\lambda_{\mathrm{L}}\right)_{\max }=\frac{4}{3} \frac{\mathrm{L}}{\mathrm{R}} \\ & \left(\lambda_{\mathrm{L}}\right)_{\max }=\frac{4}{3} \times 912 \mathop A\limits^o=4 \times 304 \mathop A\limits^o=1216 \mathop A\limits^o \\ & \left(\frac{1}{\lambda_{\mathrm{L}}}\right)_{\min }=\mathrm{R}\left(\frac{1}{(1)^2}-\frac{1}{(\infty)^2}\right) \\ & \left(\lambda_{\mathrm{L}}\right)_{\min }=\frac{1}{\mathrm{R}} \simeq 912 \mathop A\limits^o \end{aligned}$$

Range of $\lambda$ is $$912 \mathop A\limits^o$$ to $$1216 \mathop A\limits^o$$ which lies in U.V. region.