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Atoms and Nuclei question

2021 · Q131
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Atoms and Nuclei question

2021 · Q131

NEETPhysicsAtoms and NucleiMCQ+4 / −1
A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding per nucleon of unfragmented nuclei is 7.6MeV while that of fragments is 8.5MeV. The total gain in the Binding Energy in the process is :
  1. A
    216MeV
  2. B
    0.9MeV
  3. C
    9.4MeV
  4. D
    804MeV
View written solutionFree

Correct answer: A

Given binding energy per nucleon of X, Y & Z are

7.6MeV, 8.5MeV & 8.5MeV respectively,

Gain in binding energy is :

Q = Binding Energy of products −-− Binding energy of reactants

= (120 ×\times× 8.5 ×\times× 2) −-− (240 ×\times× 7.6) MeV

= 216 MeV

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