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Atoms and Nuclei question

2020 · Q127
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Atoms and Nuclei question

2020 · Q127

NEETPhysicsAtoms and NucleiMCQ+4 / −1
The energy equivalent of 0.5 g of a substance is :
  1. A
    4.5×1013J4.5 \times {10^{13}}J4.5×1013J
  2. B
    1.5×1013J1.5 \times {10^{13}}J1.5×1013J
  3. C
    0.5×1013J0.5 \times {10^{13}}J0.5×1013J
  4. D
    4.5×1016J4.5 \times {10^{16}}J4.5×1016J
View written solutionFree

Correct answer: A

E=mc2=0.5×10−3×(3×108)2=4.5×1013JE = m{c^2} = 0.5 \times {10^{ - 3}} \times {\left( {3 \times {{10}^8}} \right)^2} = 4.5 \times {10^{13}}JE=mc2=0.5×10−3×(3×108)2=4.5×1013J

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