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Atoms and Nuclei question

2000 · Q141
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Atoms and Nuclei question

2000 · Q141

NEETPhysicsAtoms and NucleiMCQ+4 / −1
Maximum frequency of emission is obtained for the transition
  1. A
    n = 2 to n = 1
  2. B
    n = 6 to n = 2
  3. C
    n = 1 to n = 2
  4. D
    n = 2 to n = 6.
View written solutionFree

Correct answer: A

ν\nu ν ∝\propto∝ [1n12−1n22]\left[ {{1 \over {n_1^2}} - {1 \over {n_2^2}}} \right][n12​1​−n22​1​]

Maximum frequency of emission happens when n1 = 1 and n2 = 2

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