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Alternating Current question

2016 · Q129
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Alternating Current question

2016 · Q129

NEETPhysicsAlternating CurrentMCQ+4 / −1
A 100 Ω\OmegaΩ resistance and a capacitor of 100 Ω\OmegaΩ reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is
  1. A
    2.2 A
  2. B
    11 A
  3. C
    4.4 A
  4. D
    112A\sqrt 2 A2​A
View written solutionFree

Correct answer: A

Net impedance, Z = R2+XL2\sqrt {{R^2} + X_L^2} R2+XL2​​ = 1002 Ω100\sqrt 2 \,\Omega 1002​Ω

Peak value of displacement current = Maximum conduction current in the circuit

= ε0Z{{{\varepsilon _0}} \over Z}Zε0​​ = 22021002{{220\sqrt 2 } \over {100\sqrt 2 }}1002​2202​​ = 2.2 A

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