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Alternating Current question

2007 · Q117
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Alternating Current question

2007 · Q117

NEETPhysicsAlternating CurrentMCQ+4 / −1
What is the value of inductance L for which the current is maximum in a series LCR circuit with C = 10 μ\muμF and ω\omegaω = 1000 s−-−1 ?
  1. A
    1 mH
  2. B
    cannot be calculated unless R is known
  3. C
    10 mH
  4. D
    100 mH
View written solutionFree

Correct answer: D

Condition for which current is maximum in a series LCR circuit is,

ω=1LC\omega = {1 \over {\sqrt {LC} }}ω=LC​1​

⇒\Rightarrow⇒ 1000 = 1L(10×106){1 \over {\sqrt {L\left( {10 \times {{10}^6}} \right)} }}L(10×106)​1​

⇒\Rightarrow⇒ L = 100 mH

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