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Thermodynamics question

2004 · Q107
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Thermodynamics question

2004 · Q107

NEETChemistryThermodynamicsMCQ+4 / −1
Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are −-− 382.64 kJ mol−-−1 and −-− 145.6 kJ mol−-−1, respectively. Standard Gibb's energy change for the same reaction at 298 K is
  1. A
    −-− 221.1 kJ mol−-−1
  2. B
    −-−339.3 kJ mol−-−1
  3. C
    −-− 439.3 kJ mol−-−1
  4. D
    −-− 523.2 kJ mol−-−1
View written solutionFree

Correct answer: B

Δ\Delta ΔG = Δ\Delta ΔH – TΔ\Delta ΔS

Δ\Delta ΔG = –382.64 × 103 J mol–1 – (298K) (–145.6 JK–1 mol–1)

= –382640 + 43388.8

= – 339251.2 J mol–1 = – 339.3 kJ mol–1

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