NEETChemistryThermodynamicsMCQ+4 / −1
If the bond energies of H H, Br Br, and H Br are 433, 192 and 364 kJ mol1 respectively, the Ho for the reaction
H2(g) + Br2(g) 2HBr(g) is
H2(g) + Br2(g) 2HBr(g) is
- A261 kJ
- B+103 kJ
- C+261 kJ
- D103 kJ
View written solutionFree
Correct answer: D
H2(g) + Br2(g) 2HBr(g), Hof = ?
Hof = (B.E.)reactants – (B.E.)products
= (B.E.)H–H + (B.E.)Br–Br –2(B.E)H-Br
= [433 + 192] – 2(364) kJ mol–1
= (625 – 728) kJ mol–1 = –103 kJ mol–1
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