NEETChemistryStructure of AtomMCQ+4 / −1
If radius of second Bohr orbit of the He+ ion is 105.8 pm, what is the radius of third Bohr orbit of Li2+ ion?
- A158.7 pm
- B15.87 pm
- C1.587 pm
- D158.7
View written solutionFree
Correct answer: A
$${r_n} \propto {{{n^2}} \over Z}$$
$${{{r_3}(L{i^{2 + }})} \over {{r_2}(H{e^ + })}} = {{{{({n_3})}^2}} \over {Z(L{i^{2 + }})}} \times {{Z(H{e^ + })} \over {{{({n_2})}^2}}}$$
$${{{r_3}(L{i^{2 + }})} \over {105.8}} = {{{{(3)}^2}} \over 3} \times {2 \over {{{(2)}^2}}}$$
$$ = 105.8 \times {3 \over 2}$$
$${r_3}(L{i^{2 + }}) = 158.7$$ pm
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