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Structure of Atom question

2021 · Q98
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Structure of Atom question

2021 · Q98

NEETChemistryStructure of AtomMCQ+4 / −1
A particular station of All India Radio, New Delhi broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light c = 3.0 ×\times× 108 ms−-−1]
  1. A
    21.92 cm
  2. B
    219.3 m
  3. C
    219.2 m
  4. D
    2192 m
View written solutionFree

Correct answer: B

Energy of electromagnetic radiation (E)

=hcλ=hγ= {{hc} \over \lambda } = h\gamma=λhc​=hγ

So, cλ=γ{c \over \lambda } = \gamma λc​=γ

⇒λ=cγ \Rightarrow \lambda = {c \over \gamma }⇒λ=γc​

λ=3×1081368×103=219.3\lambda = {{3 \times {{10}^8}} \over {1368 \times {{10}^3}}} = 219.3λ=1368×1033×108​=219.3 m

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