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Structure of Atom question

2014 · Q103
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Structure of Atom question

2014 · Q103

NEETChemistryStructure of AtomMCQ+4 / −1
Calculate the energy in joule corresponding to light of wavelength 45 nm. (Planck,s constant, h = 6.63 ×\times× 10−-−34 J s, speed of light, c = 3 ×\times× 108 m s−-−1)
  1. A
    6.67 ×\times× 1015
  2. B
    6.67 ×\times× 1011
  3. C
    4.42 ×\times× 10−-−15
  4. D
    4.42 ×\times× 10−-−18
View written solutionFree

Correct answer: D

E = hcλhc \over \lambdaλhc​

E = 6.63×10−34×3×10845×10−9{{6.63 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {45 \times {{10}^{ - 9}}}}45×10−96.63×10−34×3×108​

= 4.42 ×\times× 10-18 J

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