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Structure of Atom question

2012 · Q57
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Structure of Atom question

2012 · Q57

NEETChemistryStructure of AtomMCQ+4 / −1
The orbital angular momentum of a p-electron is given as
  1. A
    h2π{h \over {\sqrt 2 \pi }}2​πh​
  2. B
    3h2π\sqrt 3 {h \over {2\pi }}3​2πh​
  3. C
    32hπ\sqrt {{3 \over 2}} {h \over \pi }23​​πh​
  4. D
    6h2π\sqrt 6 {h \over {2\pi }}6​2πh​
View written solutionFree

Correct answer: A

Orbital angular momentum (m) = l(l+1)h2π\sqrt {l(l + 1)} {h \over {2\pi }}l(l+1)​2πh​

For p-electrons; l = 1

Thus, m = l(l+1)h2π\sqrt {l(l + 1)} {h \over {2\pi }}l(l+1)​2πh​ = 2h2π{ \sqrt 2 {h}} \over 2 \pi2π2​h​ = h2π{h \over {\sqrt 2 \pi }}2​πh​

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