NEETChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
A mixture of 2.3 g formic acid and 4.5 g oxalic
acid is treated with conc. H2SO4
. The evolved
gaseous mixture is passed through KOH
pellets. Weight (in g) of the remaining product
at STP will be
- A1.4
- B3.0
- C2.8
- D4.4
View written solutionFree
Correct answer: C
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KOH will absorb CO2 and conc. H2SO4 will absorb obtain water so in final solution only CO left.
Moles of CO formed from both reactions,
= ${1 \over {20}}$ + ${1 \over {20}}$ = ${1 \over {10}}$
$ \therefore $ Mass of CO = moles × molar mass = $${1 \over {10}} \times 28$$ = 2.8 g
KOH will absorb CO2 and conc. H2SO4 will absorb obtain water so in final solution only CO left.
Moles of CO formed from both reactions,
= ${1 \over {20}}$ + ${1 \over {20}}$ = ${1 \over {10}}$
$ \therefore $ Mass of CO = moles × molar mass = $${1 \over {10}} \times 28$$ = 2.8 g
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