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Some Basic Concepts of Chemistry question

2014 · Q99
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Some Basic Concepts of Chemistry question

2014 · Q99

NEETChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
When 22.4 liters of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P. the moles of HCl(g) formed is equal to
  1. A
    1 mol of HCl(g)
  2. B
    2 mol of HCl(g)
  3. C
    0.5 mol of HCl(g)
  4. D
    1.5 mol of HCl(g)
View written solutionFree

Correct answer: A

1 mole = 22.4 L at S.T.P

nH2 = 22.422.4{{22.4} \over {22.4}}22.422.4​ = 1 mole

nCl2 = 11.222.4{{11.2} \over {22.4}}22.411.2​ = 0.5 mole

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H2+Cl2$ \Rightarrow $2HCl(g)
Initial1 mol0.5 mol0
Final( 1 - 0.5)
= 0.5 mol		(0.5 - 0.5)
= 0 mol		2 x 0.5
1 mol

Here Cl2 is limiting reagent. So 1 mole of HCl(g) is formed.
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