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Solutions question

2024 · Q148
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Solutions question

2024 · Q148

NEETChemistrySolutionsMCQ+4 / −1

Mass of glucose (C6H12O6)(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6)(C6​H12​O6​) required to be dissolved to prepare one litre of its solution which is isotonic with 15 g L−115 \mathrm{~g} \mathrm{~L}^{-1}15 g L−1 solution of urea (NH3CONH2)(\mathrm{NH}_3 \mathrm{CONH}_2)(NH3​CONH2​) is (Given: Molar mass in gmol−1C:12,H:1,O:16, N:14\mathrm{g} \mathrm{mol}^{-1} \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16, \mathrm{~N}: 14gmol−1C:12,H:1,O:16, N:14)

  1. A
    55 g
  2. B
    15 g
  3. C
    30 g
  4. D
    45 g
View written solutionFree

Correct answer: D

For isotonic solutions [osmotic pressure must be equal]

$$\begin{aligned} & \pi_1=\pi_2 \\ & C_1 R T=C_2 R T \\ & C_1=C_2 \\ & \frac{\mathrm{m}}{180 \times 1}=\frac{15}{60 \times 1} \quad \text { ( } \mathrm{m} \text { is the mass of glucose) } \\ & \mathrm{m}=\frac{180}{4}=45 \mathrm{~g} \end{aligned}$$

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