The plot of osmotic pressure (П) vs concentration for a solution gives a straight line with slope . The temperature at which the osmotic pressure measurement is done is
(Use )
- A
- B
- C
- D
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Correct answer: A
The relationship between the osmotic pressure $(\Pi)$ of a solution and its concentration $(c)$ can be derived from the van't Hoff equation for dilute solutions, which is given by:
$\Pi = cRT$
where:
- $\Pi$ is the osmotic pressure,
- $c$ is the concentration of the solution in moles per liter,
- $R$ is the ideal gas constant in appropriate units, and
- $T$ is the temperature in Kelvin.
According to the problem, the slope of the $\Pi$ vs $c$ plot is given as $$25.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}$$ which corresponds to the product $RT$ from the van't Hoff equation. We are provided with the value of the gas constant $$R = 0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$$.
To find the temperature $T$, we use the following equation derived from the slope of the line:
$$RT = 25.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}$$
To isolate $T$, we rearrange the equation:
$$T = \frac{25.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}}{0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}} \approx 310 \mathrm{~K}$$
To convert this temperature from Kelvin to Celsius, we use the conversion formula:
$$T_{\text{Celsius}} = T_{\text{Kelvin}} - 273.15$$
$$T_{\text{Celsius}} = 310 \mathrm{~K} - 273.15 \approx 36.85^{\circ} \mathrm{C}$$
This value is closest to $$37^{\circ} \mathrm{C}$$, which corresponds to Option A. Therefore, the temperature at which the osmotic pressure measurement is done is approximately $$37^{\circ} \mathrm{C}$$.
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