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Solutions question

2024 · Q144
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Solutions question

2024 · Q144

NEETChemistrySolutionsMCQ+4 / −1

The plot of osmotic pressure (П) vs concentration (mol L−1)(\mathrm{mol} \mathrm{~L}^{-1})(mol L−1) for a solution gives a straight line with slope 25.73 L bar mol−125.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}25.73 L bar mol−1. The temperature at which the osmotic pressure measurement is done is

(Use R=0.083 L bar mol−1 K−1\mathrm{R}=0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}R=0.083 L bar mol−1 K−1)

  1. A
    37∘C37^{\circ} \mathrm{C}37∘C
  2. B
    310∘C310^{\circ} \mathrm{C}310∘C
  3. C
    25.73∘C25.73^{\circ} \mathrm{C}25.73∘C
  4. D
    12.05∘C12.05^{\circ} \mathrm{C}12.05∘C
View written solutionFree

Correct answer: A

The relationship between the osmotic pressure $(\Pi)$ of a solution and its concentration $(c)$ can be derived from the van't Hoff equation for dilute solutions, which is given by:

$\Pi = cRT$

where:

  • $\Pi$ is the osmotic pressure,
  • $c$ is the concentration of the solution in moles per liter,
  • $R$ is the ideal gas constant in appropriate units, and
  • $T$ is the temperature in Kelvin.

According to the problem, the slope of the $\Pi$ vs $c$ plot is given as $$25.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}$$ which corresponds to the product $RT$ from the van't Hoff equation. We are provided with the value of the gas constant $$R = 0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$$.

To find the temperature $T$, we use the following equation derived from the slope of the line:

$$RT = 25.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}$$

To isolate $T$, we rearrange the equation:

$$T = \frac{25.73 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1}}{0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}} \approx 310 \mathrm{~K}$$

To convert this temperature from Kelvin to Celsius, we use the conversion formula:

$$T_{\text{Celsius}} = T_{\text{Kelvin}} - 273.15$$

$$T_{\text{Celsius}} = 310 \mathrm{~K} - 273.15 \approx 36.85^{\circ} \mathrm{C}$$

This value is closest to $$37^{\circ} \mathrm{C}$$, which corresponds to Option A. Therefore, the temperature at which the osmotic pressure measurement is done is approximately $$37^{\circ} \mathrm{C}$$.

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