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Solutions question

2012 · Q99
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Solutions question

2012 · Q99

NEETChemistrySolutionsMCQ+4 / −1
pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be
  1. A
    pA+xA(pB−pA){p_A} + {x_A}\left( {{p_B} - {p_A}} \right)pA​+xA​(pB​−pA​)
  2. B
    pA+xA(pA−pB){p_A} + {x_A}\left( {{p_A} - {p_B}} \right)pA​+xA​(pA​−pB​)
  3. C
    pB+xA(pB−pA){p_B} + {x_A}\left( {{p_B} - {p_A}} \right)pB​+xA​(pB​−pA​)
  4. D
    pB+xA(pA−pB){p_B} + {x_A}\left( {{p_A} - {p_B}} \right)pB​+xA​(pA​−pB​)
View written solutionFree

Correct answer: D

p = pAxA + pBxB

= pAxA + pB(1 – xA)

(As for binary solution xA + xB = 1)

= pAxA + pB – pBxA

= pB + xA(pA – pB)

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