NEETChemistryP Block ElementsMCQ+4 / −1
Oxidation states of P in H4P2O5, H4P2O6, H4P2O7 are respectively
- A+3, +5, +4
- B+5, +3, +4
- C+5, +4, +3
- D+3, +4, +5
View written solutionFree
Correct answer: D
The oxidation state can be calculated as :
H4P2O5 : +4 + 2x + 5(– 2) = 0 2x – 6 = 0 x = +3
H4P2O6 : +4 + 2x + 6(– 2) = 0 2x – 8 = 0 x = +4
H4P2O7 : +4 + 2x + 7(– 2) = 0 2x – 10 = 0 2x = 10 x = +5
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