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Ionic Equilibrum question

2001 · Q121
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Ionic Equilibrum question

2001 · Q121

NEETChemistryIonic EquilibrumMCQ+4 / −1
Correct relation between dissociation constants of a dibasic acid is
  1. A
    Ka1 = Ka2
  2. B
    Ka1 > Ka2
  3. C
    Ka1 < Ka2
  4. D
    Ka1 = 1Ka2{1 \over {{K_{{a_2}}}}}Ka2​​1​
View written solutionFree

Correct answer: B

In polyprotic acids the loss of second proton occurs much less readily than the first. Usually the Ka values for successive loss of protons from these acids differ by at least a factor of 10–3.

∴\therefore∴ Ka1 > Ka2

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