NEETChemistryIonic EquilibrumMCQ+4 / −1
0.01 M acetic acid solution is 1% ionised, then pH of this acetic acid solution is :
- A1
- B3
- C2
- D4
View written solutionFree
Correct answer: D
For weak acid (i.e. CH3COOH)
$[{H^ + }] = C\alpha $
$$ = 0.01 \times {1 \over {100}} = {10^{ - 4}}$$ M
$$pH = - \log {H^ + } = - \log {10^{ - 4}} = 4$$
More from Ionic Equilibrum
- The pH of the solution containing 50 mL each of 0.10 M sodium acetate and 0.01 M acetic acid is [Given pKa of CH3COOH = 4.57]2022 · MCQ
- The pKb of dimethyl amine and pKa of acetic acid are 3.27 and 4.77 respectively at T (K). The correct option for the pH of dimethyl ammonium acetate solution is :2021 · MCQ
- Find out the solubility of Ni(OH)2 in 0.1M NaOH. Given that the ionic product of Ni(OH)2 is 2 10-15.2020 · MCQ
- Conjugate base for Bronsted acids H2O and HF are :2019 · MCQ
- pH of a saturated solution of Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is :2019 · MCQ
- Which will make basic buffer?2019 · MCQ
- The solubility of BaSO4 in water is 2.42 × 10–3 g L–1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol–1)2018 · MCQ
- Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations : A. 60 mL HCl + 40 mL NaOH B. 55 mL HCl + 45 mL NaOH C. 75 mL …2018 · MCQ