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Hydrocarbons question

2024 · Q103
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Hydrocarbons question

2024 · Q103

NEETChemistryHydrocarbonsMCQ+4 / −1

Given below are two statements:

Statement I: Propene on treatment with diborane gives an addition product with the formula

NEET 2024 (Re-Examination) Chemistry - Hydrocarbons Question 5 English 1

Statement II: Oxidation of

NEET 2024 (Re-Examination) Chemistry - Hydrocarbons Question 5 English 2

with hydrogen peroxide in presence of NaOH\mathrm{NaOH}NaOH gives propan-2ol.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A
    Statement I is correct but Statement II is incorrect
  2. B
    Statement I is incorrect but Statement II is correct
  3. C
    Both Statement I and Statement II are correct
  4. D
    Both Statement I and Statement II are incorrect
View written solutionFree

Correct answer: B

$$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2+\left(\mathrm{H}-\mathrm{BH}_2\right)_2 \longrightarrow \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{BH}_2 \xrightarrow{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2}\left(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2\right)_2 \mathrm{BH}$$

$$ \xrightarrow{\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2}\left(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2\right)_3 \mathrm{~B} \xrightarrow{\mathrm{H}_2 \mathrm{O}_2 / \bar{\mathrm{OH}}}$$ $$\mathrm{\mathop {C{H_3} - C{H_2} - C{H_2} - OH}\limits_{\Pr opan - 1 - ol\,(Major)}}$$

NEET 2024 (Re-Examination) Chemistry - Hydrocarbons Question 5 English Explanation

Statement I is incorrect but Statement II is correct.

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