NEETChemistryHydrocarbonsMCQ+4 / −1
The decreasing order of boiling points of the following alkanes is :
(a) heptane
(b) butane
(c) 2-methylbutane
(d) 2-methylpropane
(e) hexane
Choose the correct answer from the options given below :
- A(a) > (e) > (c) > (b) > (d)
- B(a) > (c) > (e) > (d) > (b)
- C(c) > (d) > (a) > (e) > (b)
- D(a) > (e) > (b) > (c) > (d)
View written solutionFree
Correct answer: A
$\bullet$ With increase in number of carbons in alkane, boiling point increases
$\bullet$ In case of isomeric alkanes, greater is the number of branches, lesser is the boiling point.
Boiling point order : $$\mathop {\mathrm{Heptan e}}\limits_{(a)} > \mathop {\mathrm{Hexane}}\limits_{(e)} > \mathop {\mathrm{2 - methylbutane}}\limits_{(c)} > \mathop {\mathrm{butane}}\limits_{(b)} > \mathop {2 - \mathrm{methylpropane}}\limits_{(d)} $$
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