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Electrochemistry question

2012 · Q66
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Electrochemistry question

2012 · Q66

NEETChemistryElectrochemistryMCQ+4 / −1
Molar conductivities (Λmo)\left( {\Lambda _m^o} \right)(Λmo​) at infinite dilution of NaCl, Hcl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol−-−1 respectively. (Λmo)\left( {\Lambda _m^o} \right)(Λmo​) for CH3COOH will be
  1. A
    425.5 S cm2 mol−-−1
  2. B
    180.5 S cm2 mol−-−1
  3. C
    290.8 S cm2 mol−-−1
  4. D
    390.5 S cm2 mol−-−1
View written solutionFree

Correct answer: D

Λ\Lambda ΛoCH3COOH = Λ\Lambda ΛoCH3COONa + Λ\Lambda ΛoHCl - Λ\Lambda ΛoNaCl

= = 91 + 425.9 – 126.4 = 390.5

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