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Chemical Kinetics question

2022 · Q130
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Chemical Kinetics question

2022 · Q130

NEETChemistryChemical KineticsMCQ+4 / −1

For a chemical reaction

4A + 3B →\to→ 6C + 9D

Rate of formation of C is 6 ×\times× 10−-−2 mol L−-−1 s−-−1 and rate of disappearance of A is 4 ×\times× 10−-−2 mol L−-−1 s−-−1. The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be :

  1. A
    10 ×\times× 10−-−2 mol L−-−1 s−-−1 and 30 ×\times× 10−-−2 mol L−-−1
  2. B
    1 ×\times× 10−-−2 mol L−-−1 s−-−1 and 30 ×\times× 10−-−2 mol L−-−1
  3. C
    10 ×\times× 10−-−2 mol L−-−1 s−-−1 and 10 ×\times× 10−-−2 mol L−-−1
  4. D
    1 ×\times× 10−-−2 mol L−-−1 s−-−1 and 10 ×\times× 10−-−2 mol L−-−1
View written solutionFree

Correct answer: B

4A + 3B $\to$ 6C + 9D

Rate of reaction = $${{ - d[A]} \over {dt}} \times {1 \over 4} = {{ - d[B]} \over {dt}} \times {1 \over 3} = {{ + d[C]} \over {dt}} \times {1 \over 6} = {{ + d[D]} \over {dt}} \times {1 \over 9}$$

Rate of reaction $$ = {{ + d[C]} \over {dt}} \times {1 \over 6} = {{6 \times {{10}^{ - 2}}} \over 6} = {10^{ - 2}}$$ mol L$-$1 s$-$1

Rate of reaction $$ = {{ - 1} \over 3}{{d[B]} \over {dt}}$$

$${{ - d[B]} \over {dt}} = 3 \times $$ rate of reaction $$ = 3 \times {10^{ - 2}}$$ mol L$-$1 s$-$1

After interval of 10 sec. $$ = 3 \times {10^{ - 2}} \times 10$$

$$ = 30 \times {10^{ - 2}}$$ mol L$-$1

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