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Chemical Kinetics question

2020 · Q104
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Chemical Kinetics question

2020 · Q104

NEETChemistryChemical KineticsMCQ+4 / −1
The rate constant for a first order reaction is 4.606 ×\times× 10-3 s-1. The time required to reduce 2.0 g of the reactant to 0.2 g is :
  1. A
    200 s
  2. B
    500 s
  3. C
    1000 s
  4. D
    100 s
View written solutionFree

Correct answer: B

k=(2.303t)k = \left( {{{2.303} \over t}} \right)k=(t2.303​) log(A0A)\left( {{{{A_0}} \over A}} \right)(AA0​​) for first order reaction

4.606×10−3=(2.303t)4.606 \times {10^{ - 3}} = \left( {{{2.303} \over t}} \right)4.606×10−3=(t2.303​) log(20.2)\left( {{2 \over {0.2}}} \right)(0.22​)

⇒\Rightarrow⇒ t = 500 s

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