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Work Power and Energy question

2024 · 9 Apr · Shift 1 · Q67
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  5. /2024 · 9 Apr · Shift 1 · Q67

Work Power and Energy question

2024 · 9 Apr · Shift 1 · Q67

JEE MainPhysicsWork Power and EnergyMCQ+4 / −1
A particle of mass mmm moves on a straight line with its velocity increasing with distance according to the equation v=αxv=\alpha \sqrt{x}v=αx​, where α\alphaα is a constant. The total work done by all the forces applied on the particle during its displacement from x=0x=0x=0 to x=dx=\mathrm{d}x=d, will be :
  1. A
    m2α2 d\frac{\mathrm{m}}{2 \alpha^2 \mathrm{~d}}2α2 dm​
  2. B
    md2α2\frac{\mathrm{md}}{2 \alpha^2}2α2md​
  3. C
    mα2 d2\frac{\mathrm{m} \alpha^2 \mathrm{~d}}{2}2mα2 d​
  4. D
    2 mα2 d2 \mathrm{~m} \alpha^2 \mathrm{~d}2 mα2 d
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