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Work Power and Energy question

2004 · Shift 0 · Q159
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Work Power and Energy question

2004 · Shift 0 · Q159

JEE MainPhysicsWork Power and EnergyMCQ+4 / −1
A force F→=(5i→+3j→+2k→)N\overrightarrow F = \left( {5\overrightarrow i + 3\overrightarrow j + 2\overrightarrow k } \right)NF=(5i+3j​+2k)N is applied over a particle which displaces it from its origin to the point r→=(2i→−j→)m.\overrightarrow r = \left( {2\overrightarrow i - \overrightarrow j } \right)m.r=(2i−j​)m. The work done on the particle in joules is
  1. A
    +10+10+10
  2. B
    +7+7+7
  3. C
    −7-7−7
  4. D
    +13+13+13
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