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Waves question

2021 · 20 Jul · Shift 1 · Q68
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Waves question

2021 · 20 Jul · Shift 1 · Q68

JEE MainPhysicsWavesNumerical+4 / −1
The amplitude of wave disturbance propagating in the positive x-direction is given by y=1(1+x)2y = {1 \over {{{(1 + x)}^2}}}y=(1+x)21​ at time t = 0 and y=11+(x−2)2y = {1 \over {1 + {{(x - 2)}^2}}}y=1+(x−2)21​ at t = 1 s, where x and y are in metres. The shape of wave does not change during the propagation. The velocity of the wave will be ‾\underline{\hspace{2cm}}​ m/s.
Numerical answer
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