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Wave Optics question

2021 · 27 Aug · Shift 2 · Q57
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Wave Optics question

2021 · 27 Aug · Shift 2 · Q57

JEE MainPhysicsWave OpticsMCQ+4 / −1
The light waves from two coherent sources have same intensity I1 = I2 = I0. In interference pattern the intensity of light at minima is zero. What will be the intensity of light at maxima?
  1. A
    I0
  2. B
    2 I0
  3. C
    5 I0
  4. D
    4 I0
View written solutionFree

Correct answer: D

  1. Use the interference intensity formula

For two coherent sources with intensities I1I_1I1​ and I2I_2I2​, the resultant intensity is

I=I1+I2+2I1I2cos⁡ϕI = I_1 + I_2 + 2\sqrt{I_1 I_2}\cos\phiI=I1​+I2​+2I1​I2​​cosϕ

where ϕ\phiϕ is the phase difference.

  1. Given data

I1=I2=I0I_1 = I_2 = I_0I1​=I2​=I0​

So,

I=I0+I0+2I0⋅I0cos⁡ϕI = I_0 + I_0 + 2\sqrt{I_0\cdot I_0}\cos\phiI=I0​+I0​+2I0​⋅I0​​cosϕ

I=2I0+2I0cos⁡ϕI = 2I_0 + 2I_0\cos\phiI=2I0​+2I0​cosϕ

  1. Condition for minima

At minima, cos⁡ϕ=−1\cos\phi = -1cosϕ=−1.

Thus,

Imin⁡=2I0−2I0=0I_{\min} = 2I_0 - 2I_0 = 0Imin​=2I0​−2I0​=0

This matches the given statement that intensity at minima is zero.

  1. Condition for maxima

At maxima, cos⁡ϕ=1\cos\phi = 1cosϕ=1.

Thus,

Imax⁡=2I0+2I0=4I0I_{\max} = 2I_0 + 2I_0 = 4I_0Imax​=2I0​+2I0​=4I0​

  1. Check options
  • A: I0I_0I0​ — incorrect
  • B: 2I02I_02I0​ — incorrect
  • C: 5I05I_05I0​ — incorrect
  • D: 4I04I_04I0​ — correct

Therefore, the intensity at maxima is

4I0\boxed{4I_0}4I0​​

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