Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Wave Optics question

2015 · Shift 0 · Q49
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Physics
  4. /Wave Optics
  5. /2015 · Shift 0 · Q49

Wave Optics question

2015 · Shift 0 · Q49

JEE MainPhysicsWave OpticsMCQ+4 / −1
On a hot summer night, the refractive index of air is smallest near the ground and increases with height from the ground. When a light beam is directed horizontally, the Huygens' principle leads us to conclude that as it travels, the light beam :
  1. A
    bends down wards
  2. B
    bends upwards
  3. C
    becomes narrower
  4. D
    goes horizontally without any deflection
View written solutionFree

Correct answer: B

  1. Given situation

    The refractive index of air is:

    • smallest near the ground
    • increases with height

    So, if a horizontal light beam travels close to the ground, the upper part of the wavefront is in air of higher refractive index than the lower part.

  2. Use of Huygens’ principle

    By Huygens’ principle, every point on a wavefront acts as a source of secondary wavelets.

    The speed of light in a medium is v=cnv = \frac{c}{n}v=nc​

    Hence:

    • where nnn is smaller, speed is larger
    • where nnn is larger, speed is smaller

    Since near the ground nnn is smaller, the lower part of the wavefront moves faster than the upper part.

  3. Effect on the wavefront

    Because the lower portion advances more quickly than the upper portion, the wavefront tilts in such a way that the ray direction changes toward the region of higher refractive index.

    Since refractive index increases upward, the beam bends upward.

  4. Option analysis

    • A: bends downwards — Incorrect
    • B: bends upwards — Correct
    • C: becomes narrower — Incorrect
    • D: goes horizontally without any deflection — Incorrect
  5. Final answer

    The light beam bends toward higher refractive index, i.e. upwards.

PreviousNext

More from Wave Optics

  • Two beams, A and B, of plane polarized light with mutually perpendicular planes of polarization are seen through a polaroid. From the position when the beam A has maximum intensity (and beam B has zero intensity), a rotation of…2014 · MCQ
  • Two coherent point sources S1​ and S2​ are separated by a small distance ′d′ as shown. The fringes obtained on the screen will be Includes diagram2013 · MCQ
  • A beam of unpolarised light of intensity I0​ is passed through a polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 45∘ relative to that of A. The…2013 · MCQ
  • In Young's double slit experiment , one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If Im​ be the maximum intensity, the resultant intensity I when they…2012 · MCQ
  • This question has a paragraph followed by two statements, Statement −1 and Statement −2. Of the given four alternatives after the statements, choose the one that describes the statements. A thin air film is formed by putting the convex…2011 · MCQ
  • An initially parallel cylindrical beam travels in a medium of refractive index μ(I)=μ0​+μ2​I, where μ0​ and μ2​ are positive constants and I is the intensity of the light beam. The…2010 · MCQ
  • A mixture of light, consisting of wavelength 590nm and an unknown wavelength, illuminates Young's double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it…2009 · MCQ
  • In a Young's double slit experiment the intensity at a point where the path difference is 6λ​(λ being the wavelength of light used ) is I. If I0​ denotes the maximum intensity, I0​I​ is equal to2007 · MCQ